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The optical rotation of a solution of pure natural camphor is found to be +5.76^(@) under the following conditions, concentration = 0.13g/ml, length of polarimeter = 1dm, wavelength = sodium D line, T=25^(@)C. The specific rotation of camphor is |
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Answer» `+44.3^@` `((alpha) " = Observed angle of rotation" (THETA))/(c XX 1)` ` = (+576)/(0.13 xx 1) = + 44.3^@` |
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