1.

The optical rotation of a solution of pure natural camphor is found to be +5.76^(@) under the following conditions, concentration = 0.13g/ml, length of polarimeter = 1dm, wavelength = sodium D line, T=25^(@)C. The specific rotation of camphor is

Answer»

`+44.3^@`
`+26.7^@`
`-26.7^@`
`-44.3^@`

SOLUTION :`[ALPHA]` = specific ROTATION of comphor
`((alpha) " = Observed angle of rotation" (THETA))/(c XX 1)`
` = (+576)/(0.13 xx 1) = + 44.3^@`


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