1.

The orbital angular momentum of a p-electron is given as:

Answer»

`SQRT((3)/(2)) (h)/(PI)`
`sqrt6 (h)/(2PI)`
`(h)/(sqrt2pi)`
`sqrt3 (h)/(2pi)`

Solution :For p-obrbital, `l = 1`
Orbital angular momentum
`= sqrt(l(l + 1)) (h)/(2pi) = sqrt(1(1 + 1)) (h)/(2pi)`
`= SQRT2 (h)/(2pi) =(h)/(sqrt2pi)`


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