Saved Bookmarks
| 1. |
The orbital radius of mercury around the sun is 0.38 A U. Determine the angle of maximum elogation for mercury and its distance from earth, where elognation is maximum, |
|
Answer» The angle of maximum elongation `"in"`is given by `SIN "in" = (r_(ps))/(r_(es)) = (0.38)/(1)` Now,`r_(pe) =r_(es)xxcos "in"` `1.496xx10^(11) cos (22.3^@)` `=1.496xx10^(11)xx0.9252 = 1.384xx10^(11)m` `=1.384xx10^8km` |
|