1.

The orbital velocity of a body close to the earth's surface is

Answer»

`8 "kms"^(-1)`
`11.2 "kms"^(-1)`
`3 xx 10^(8) "ms"^(-1)`
`2.2 xx 10^(3) "kms"^(-1)`

Solution :Since, orbital velocity of BODY close to earth can be given as
`v_(o)=SQRT(RG)=sqrt(6400xx10^(3)xx10)=sqrt(64xx10^(6))=8xx10^(3) " ms"^(-1)`
`v_(o)=8 " kms"^(-1)`.


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