1.

The orbital velocity of a satellite in a circular orbit close to the earth is v_0 . If the escape velocity of an object projected from the earth be v_e,then the ratio of these two velocities is

Answer»

`1:1`
`sqrt(2):1`
`sqrt(3):1`
`2:1`

SOLUTION :`(v_e)/(v_0)= sqrt((2gR)/(sqrt(GR)))=sqrt(2)/1`


Discussion

No Comment Found