1.

The orbital velocity of an artificial in a circular orbit justabove the earth's surface v. For a satellite orbiting at an altitude of half the earth's radius the orbital velocity is

Answer»

`(3)/(2)` v
`sqrt((3)/(2))` v
`sqrt((2)/(3))` v
`(2)/(3)` v

Solution :Since, ORBITAL velocity `v=sqrt((GM)/(R))or v prop (1)/(sqrt(r))`
`(v_(2))/(v_(1))=sqrt((r_(1))/(r_(2)))`
`:. v_(2)=sqrt((r_(1))/(r_(2))).v=sqrt((R)/(R+(R)/(2))).v=sqrt((2)/(3))v`.


Discussion

No Comment Found