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The order in which the reagent must be used to separate the compound I-IV is: A. `NaOH,NaHCO_3,HCl`B. `HCl, NaOH, NaHCO_3`C. `NaHCO_3, NaOH, HCl`D. `NaOH, HCl,NaHCO_3` |
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Answer» Correct Answer - C It is soluble in `NaHCO_3` , I is soluble in NaOH and III is soluble in HCl. |
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