1.

The order of a gaseous phase reaction for which rate becomes half if volume of container having same amount of reactant is doubled is

Answer»

1
`1//2`
2
`1//3`

Solution :`r_1= k [A]^n`…(i)
where n is order of REACTION.
When `V_("FINAL")= 2V_("initial")," then " r_2=k[A/(2V)]^n=1/2…(ii)`
and `r_2= 1/2r_1`
Dividing (ii) by (i)
`:. 2 = 2^n or n = 1`


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