1.

The order of increasing freezing point of C_2H_5OH, Ba_3(PO_4)_2 , Na_2SO_4 , KCl and Li_3PO_4 is

Answer»

`Ba_3(PO_4)_2 lt Na_2SO_4 lt Li_3PO_4 lt C_2H_5OH lt KCl`
`Ba_3(PO_4)_2 lt C_2H_5OHlt Li_3PO_4 lt C_2H_5OH lt KCl`
`C_2H_5OH lt KCl lt Na_2SO_4 lt Ba_3(PO_4)_2 lt Li_3PO_4`
`Ba_3(PO_4)_2 lt Li_3PO_4 lt Na_2SO_4 lt KCl lt C_2H_5OH`

Solution :`DeltaT_f PROP i`
`i` for `C_2H_5OH=1,i` for `Ba_3(PO_4)_2=5,i` for `Na_2SO_4 =3`
`i` for `Li_3PO_4` = 4 , `i` for KCl =2
THUS , depression in FREEZING point will be in order :
`C_2H_5OH lt KCl lt Na_2SO_4 lt Li_3PO_4 lt Ba_3(PO_4)_2`
Thus, freezing point will be in order :
`Ba_3(PO_4)_2 lt Li_3PO_4 lt Na_2SO_4 lt KCl lt C_2H_5OH`


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