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The origin and the roots if the equation z2+pz+q from an equitorial triangle if(a) p2=q(b) p2=3q(c) q2=3p(d) p2=q |
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Answer» z2+pz+q=0 z1+z2 = p, z1z2=q If z1,z2,z3 are the vertices of an equilateral triangle then z12+z22+z32 = z1z2+z2z3+z3z1 If z3 is origin then z12+z22=z1z2 => (z1+z2)2=3z1z2 => p2 = 3q |
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