1.

The osmotic pressure in atmospheres of 10% solution of canesugar at 69^(@)C is

Answer»

724
824
`8.21`
`7.21`

SOLUTION :`pi V = NRT`
`pi=(w)/(m)(RT)/(V)=(10)/(342)xx(0.821xx(273+69))/(0.1)=8.21` atm


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