1.

The osmotic pressure of a solution contaiining 1.0 g protenin in 200 mL of aqueous solution at 27^(@)C has been found to be 2.0xx10^(-1)atm. Calculate the molecular mass of protein. (R=0.82 L atm mol^(-1)).

Answer»


Solution :`W_(B)=1.0g, V=200mL=0.2 L, T=273^(@)C=27+273=300K, pi=2.0xx10^(-1)ATM`
`R=0.082" L atm mol"^(-1)K^(-1),M_(B)=?`
`M_(B)=(W_(B)xxRxxT)/(pixxV)=((1G)xx(0.082" L atm K"^(-1)mol^(-1))xx(300K))/((2xx10^(-1)atm)xx(0.2L))=615.7" G mol"^(-1)`.


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