Saved Bookmarks
| 1. |
The osmotic pressure of solution containing `34.2 g` of cane sugar (molar mass = 342 g `mol^(-1)` ) in 1 L of solution at `20^(@)C` is (Given `R = 0.082` L atm `K^(-1) mol^(-1)` )A. 2.40 atmB. 3.6 atmC. 24 atmD. 0.0024 atm |
|
Answer» Correct Answer - A Data: `W_(2) = 34.2 g, M_(2) = 342 gmol^(-1),V=1 L` `T = 20 xx 273 = 293 K` and `R=0.082 L atm K^(-1), pi=?` Calculation: To calculate `pi` `pi= n_(2)RT` `pi = W_(2)/M_(2) xx (RT)/V` `=(34.2 g xx 0.082 L. atm K^(-1) mol^(-1) xx 293 K)/(342 g mol^(-1) xx 1L)` `=(34.2 xx 82 xx 293 xx 10^(-3))/(342)` atm `pi = 2.40` atm |
|