InterviewSolution
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InterviewSolution
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The osmotic pressure of urea solution is `500 mm` at `10^(@)C`. The solution is diluted and the temperature raised to `25^(@)C`, when the osmotic pressure is found to be `105.3 mm`. Find the extend if dilution. |
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Answer» Correct Answer - 5 `because pi V = nST` Initially `pi_(1) = (500)/(760)atm, T_(1) = 283K` `(500)/(760) xx V_(1) = nS xx 283` …(1) Let on dilution, the volume become `V_(2)` and temperature raise to `25^(@)C` i.e., `298K` `pi_(2) = (105.3)/(760)` Now `(105.3)/(760) xx V_(2) = nS xx 298` ...(2) By eq. (1) and (2) `(V_(1))/(V_(2)) = (283)/(298) xx (105.3)/(500)` `:. V_(1)//V_(2) = 1//5` or `V_(2) = 5V_(1)` `:.` Solution is `5` times diluted. |
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