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| 1. |
The outer electronic configurations of two transition metals are (i) 3d^(5)4s^(2) and (ii) 3d^(6)4s^(2) respectively. Based on this information predict the relative stability of +2 and +3 oxidation state of these metals. Which of the two exhibits larger number of oxidation states ? |
| Answer» Solution :Metal with configuration `3d^(5)4s^(2)` will show oxidation state (+2) more readily because of greater STABILITY of half-filled d-orbitals. Metal with configuration `3d^(6)4s^(2)` will be more stable in +3 oxidation state than +2 due because after losing two ELECTRONS the configuration of the metal ION will be `3d^(5)`, which is a stable configuration. | |