1.

The oxidation number and the electronic configuration of sulphur in H_(2)SO_(4) is

Answer»

`+3, 1S^(2) 2s^(2) 2P^(6) 3s^(2) 3p^(1)`
`+6, 1s^(2) 2s^(2) 2p^(6)`
`+4: 1s^(2) 2s^(2) 2p^(6) 3s^(2)`
`+2, 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(2)`

SOLUTION :Let x be the oxidation number of S in `H_(2)SO_(4)`
`2 + x -2 xx 4= 0 rArr 2 + x - 8 = 0 rArr x6 " " :.` Oxidation No. 6,
Electronic configuration is `2s^(2) 2p^(6)`
Oxidation state = +6


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