The oxidation number of carbon is zero is

1.	The oxidation number of carbon is zero is
Answer» HCHO `CH_2Cl_2` `C_(6)H_(12)O_6` `C_(12)H_(22)O_(11)` Solution :CONSIDER the oxidation state of .c. as .x. a) `HCHO =1 + x +1 -2 =0 impliesx =0` b) `CH_(2)Cl_(2)=x+2(1)+2(-1)=0` `x+2-2=0 implies x = 0` c) `C_(6)H_(12)O_(6)=6 (x) + 12 (1) +6(-2)=0` `6x +12 -12 = 0 implies 6x =0 :. x = 0 ` d) `C_(12)H_(22)O_(11)=12(x) +22(1)+11(-2)=0` `12X +22-22=0 implies x =0`

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