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The oxidation number of `Co ` in ` [Co(NH_(3))_(3)(NO_(2))_(3)]` isA. `+3`B. `0`C. `-3`D. `6` |
Answer» Correct Answer - A Oxidation state of `NH_(3) =0 and NO_(2)=-1` So `[Co (NH_(3))_(3) (NO_(2))_(3)]` Let , x be the charge on co ` x+(0) 3 +(-1) 3=0 implies x-3=0` ` implies x=+3` |
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