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The oxidation number of `Cr` in `K_(2)Cr_(2)O_(7)` isA. `-2`B. `-7`C. `+2`D. `+6` |
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Answer» Correct Answer - D `K_(2)overset(*)(C ) r_(2)O_(7)` `2+2x-2xx7=0`, `2x-14+2=0` `2x=12`, `x=(12)/(2)=+6` |
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