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The oxidation number of Cr in the product of alkaline oxidative fusion of `FeCr_2O_4` is |
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Answer» Correct Answer - 6 `4FeCr_2O_4+16NaOH+7O_2to8Na_2CrO_4+2Fe_2O_3+8H_2O` Let the oxidation state of Cr in `CrO_4^(2-)` is x. So x+4(-2)=-2 or x=6 |
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