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The oxidation number of iron in brown ring complexes +x. What is value of x. |
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Answer» Solution :The BROWN ring complex compound is GIVEN as: `[Fe(H_(2)O)_(5)NO] SO_(4)`. The complex ion is `[Fe(H_(2)O)_(5))NO]^(2+)` Oxidation number of `H_(2)O` is zero and NO is +1. Oxidation state of Fe is +1. Experimentally, the number of UNPAIRED ELECTRONS also support +1 state of Fe (But not +2 state). |
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