1.

The oxidation number of iron in the compound `K_(4)[Fe(CN)_(6)]` isA. `+`2B. `+4`C. `+3`D. `+6`

Answer» Correct Answer - A
`K_(4)[overset(*)(F)e(CN)_(6)]`
`1xx4+x+(-1xx6)=0`, `4+x-6=0`.
`x=+2`.
In this complex compound iron show `+2` oxidation state.


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