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The oxidation number of iron in the compound `K_(4)[Fe(CN)_(6)]` isA. `+`2B. `+4`C. `+3`D. `+6` |
Answer» Correct Answer - A `K_(4)[overset(*)(F)e(CN)_(6)]` `1xx4+x+(-1xx6)=0`, `4+x-6=0`. `x=+2`. In this complex compound iron show `+2` oxidation state. |
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