The oxidation number of K in K_(2)O,K_(2)O_(2)andKO_(2) respectively is …
Answer»
`+0.5,+4,+1` `+2,+1,+0.5` `+1,+1,+1` `+0.5,+1,+2`
SOLUTION :ALKALIMETALS always possess a +1 oxidation state, whereas oxygen present in `K_(2)O` (oxide) is -2, and in `K_(2)O_(2)` (peroxide) is -1 and in `KO_(2)` (superoxide) is `-1/2`.