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The oxidation number of Mn in the product of alkaline oxidative fusion of `MnO_2` isA. `3` electrons in neutral mediumB. `5` electrons in neutral mediumC. `3` electrons in alkaline mediumD. `5` electrons in acidic medium |
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Answer» Correct Answer - ACD in acidic medium,`" "`MnO_(4)^(-)+8H^(+)+5e^(-) to Mn^(2+)+4H_(2)O` `(V.f=5)` `"in neutral//faintly alkaline medium"," " `MnO_(4)^(-)+2H_(2)O+3E^(-) to MnO_(2)+4OH^(-)` (v.f.=3) "In strong alkaline medium"," " MnO_(4)^(-)+e^(-) to MnO_(4)^(2-)` (v.f.=1) |
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