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The oxidation number of N and Cl in `NOClO_(4)` respectively areA. `+2 " and " +7`B. `+3 " and " +7`C. `-3 " and " +5`D. `+2 " and " -7` |
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Answer» Correct Answer - B `NOClO_(4)` is actually `NO^(+)ClO_(4)^(-)` is x. `N overset(+)(O): x + (-2) = +1` `x = +1 + 2 = +3` Let the oxidation state of Cl in `ClO_(4)^(-)` is y. `ClO_(4)^(-) : y + (-2) xx 4 = -1` `y - 8 = 1, y = +7` |
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