1.

The oxidation number of N and Cl in `NOClO_(4)` respectively areA. `+2 and +7`B. `+3 and +7`C. `-3 and +5`D. `+2 and -7`

Answer» Correct Answer - B
`NOClO_(4)-=(NO^(+))(ClO_(4)^(-))` Let O.N. of N in `NO^(+)` is x
`:. x + (-2)=+1`
`x=3`
Let O.N of Cl in `ClO_(4)^(-)` is x
`:. x + 4 (-2)=-1 or x = +7`.


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