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The oxidation number of N in `NH_(4)Cl` isA. `+5`B. `+3`C. `-5`D. `-3` |
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Answer» Correct Answer - D `NH_(4)Cl" "NH_(4)^(+)+Cl^(-)` `overset(**)(N)H_(4)^(+)` `x+4=+1, x=1-=-3`. |
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