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The oxidation number of nitrogen atoms in `NH_(4)NO_(3)` are:A. `+3, +3`B. `+3,-3,`C. `-3,+5,`D. `-5,+3` |
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Answer» Correct Answer - 3 `NH_(4)NO_(3) to NH_(4)^(+) +NO_(3)^(-)` `" "N=-3" "N=+5` |
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