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The oxidation number of oxygen in `KO_(3), Na_(2)O_(2)` isA. `3, 2`B. `1,0`C. `0, 1`D. `-0.33, -1` |
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Answer» Correct Answer - D Let oxidation number of oxygen `=x` O.N. of oxygen in `KO_(3)=1+3x=0` `:. X=-1//3=-0.33` O.N. of oxygen in `Na_(2)O_(2)=2xx1+2x=0" ":. X=-1`. |
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