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The oxidation number of oxygen in `KO_(3), Na_(2)O_(2)` isA. `3, 2`B. `1,0`C. `0, 1`D. `-0.33, -1`

Answer» Correct Answer - D
Let oxidation number of oxygen `=x`
O.N. of oxygen in `KO_(3)=1+3x=0`
`:. X=-1//3=-0.33`
O.N. of oxygen in `Na_(2)O_(2)=2xx1+2x=0" ":. X=-1`.


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