The oxidation number of Pd in K2 [ PdCl4 ] is

1.	The oxidation number of Pd in K2 [ PdCl4 ] is
Answer» Answer: 2 Explanation: 2(1) + X + 4(-1) = 0 ( let the oxidation NUMBER of PD be x ) 2 + x -4 = 0 x = 2 please mark me as brainliest and please follow me

Answer»

Answer:

Explanation:

2(1) + X + 4(-1) = 0 ( let the oxidation NUMBER of PD be x )

2 + x -4 = 0

x = 2

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