1.

The oxidation number of S in Na_(2) S_(4)O_(6)is

Answer»

`+ 2.5`
 ` + 2 and + 3`(TWO S have + 2 and other two have +3)
+ 2 and + 3 (THREE S have + 2 and one S has + 3)
` + 5 and 0` (two S have + 5 and the other two S have 0)

Solution :`Na_(2)S_4O_6:NaO-underset(O)underset(+5||"")overset(O)overset(||)S-overset(0)S-overset(0)S-overset(O)overset(||)underset(O)underset(||+5)S-ONa`


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