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The oxidation number of sulphur in `H_(2)S_(2)O_(7)` and iron in `K_(4)Fe(CN)_(6)` is respectivelyA. `+6` and `+2`B. `+2` and `+2`C. `+8` and `+2`D. `+6` and `+4` |
Answer» Correct Answer - A `H_(2)overset(*)(S_(2))O_(7)` `2xx(+1)+2xx x+7xx(-2)=0` `+2+2x-14=0` `2x=14-2=12` `x=(12)/(2)=+6` for `S` `K_(4)overset(*)(F)e(CN)_(6)` `4xx(+1)x+6xx(-1)=0` `4+x-6=0` `x=6-4=+2` for `Fe`. |
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