The oxidation number of sulphur in `Na_2S_4O_6` is .A. ` 1.5`B. ` 2.5`C. ` 3.0`D. ` 2.0`

The oxidation number of sulphur in `Na_2S_4O_6` is .A. ` 1.5`B. ` 2.5`

1.	The oxidation number of sulphur in `Na_2S_4O_6` is .A. ` 1.5`B. ` 2.5`C. ` 3.0`D. ` 2.0`
Answer» Correct Answer - B The algebraic sum of the the oxidation numbers of all the atoms in a compound must be zero . Let the the oxidation number of S be x . Then Note that this is the average oxidation number of S in ` Na_2S_4O_6`. In fact, two S atoms have an oxidation state of zero while other two S atoms have an oxidation state of `+5` each as shown by its structure : `Na^(+)overset(-)(O)-underset(O)underset(\|\|)overset(O)overset(\|\|)(S)overset(+5)(-)overset(0)(S)-overset(0)(S)overset(+5)(-)underset(O)underset(\|\|)overset(O)overset(\|\|)(S)-overset(-)(O)Na^(+)`

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The oxidation number of sulphur in `Na_2S_4O_6` is .A. ` 1.5`B. ` 2.5`C. ` 3.0`D. ` 2.0`

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