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The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is: |
Answer» Correct Answer - D Let the oxidation state of `Cr=x, NH_(3) =0 ,Cl=-1` Net charge =+1 `therefore [Cr(NH_(3))_(4) Cl_(2)]^(+)` `x+4xx0+2(-1) =+1` ` therefore x=+3` |
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