1.

The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:

Answer» Correct Answer - D
Let the oxidation state of `Cr=x, NH_(3) =0 ,Cl=-1`
Net charge =+1
`therefore [Cr(NH_(3))_(4) Cl_(2)]^(+)`
`x+4xx0+2(-1) =+1`
` therefore x=+3`


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