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The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:A. `+2`B. `+3`C. `+4`D. `+5` |
Answer» Correct Answer - A `[Cr(NH_3)_4Cl_2]^(+)` x + 4(0) + 2(-1) + +1 x = +1 + 2 = +3 |
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