1.

The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:A. `+2`B. `+3`C. `+4`D. `+5`

Answer» Correct Answer - A
`[Cr(NH_3)_4Cl_2]^(+)`
x + 4(0) + 2(-1) + +1
x = +1 + 2 = +3


Discussion

No Comment Found