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The oxidation state of `Cr` in `[Cr(NH_(3))_(4)Cl_(2)]^(+)` is:A. `+3`B. `+2`C. `+1`D. 0 |
Answer» Correct Answer - A `[Cr(NH_(3))_(4)Cl_(2)]^(+)` Let O.S. of Cr = x `x + 4 xx 0 + 2 xx (-1) = +1` `x -2 = 1` x = `+3` |
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