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The oxidation state of Fe in brown complex `[Fe(H_(2)O)_(5)NO]SO_(4)` isA. `+1`B. `+2`C. `+3`D. `+4` |
Answer» Correct Answer - A Oxidation state of Fe in `[Fe(H_(2)O)_(5)NO]SO_(4) is +1` as water `(H_(2)O)` is a neutral ligands with `NO^(+) -a` postivie ligand NO is an odd electron molecule . It gives its one unpaired electron to `Fe^(2+)` |
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