1.

The oxidation state of Fe in the brown ring complex [Fe(H_(2)O)_5No]SO_(4) is

Answer»

0
`+2`
`+1`
`+3`

Solution :Let the oxidation of Fe in `[Fe(H_(2)O)_(5)NO]^(2+)`be x.
CHARGE of `H_(2)O` and NO is ZERO as both are neutral ligands.
`:.x+0+0=2impliesx=+2`
`:.` Oxidation state of `Fe=+2`.


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