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The oxidation state of oxygen in `O_2[PtF_6]` isA. (a) zeroB. (b) `-1//2`C. (c) `+1`D. (d) `+1//2` |
Answer» Correct Answer - D `O_2[PtF_6]` is considered to be formed from `O_2^+` and `[PtF_6]^(1-)`. In `O_2^(+1)`, oxidation state of `O` is `2x=+1`. `x=+1/2` |
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