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The oxidation state of `S` in `H_(2)S_(2)O_(8)` isA. `+6`B. `+7`C. `+8`D. 0 |
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Answer» Correct Answer - A `H_(2)S_(2)O_(8)` `H-O-underset(O)underset(||)overset(O)overset(||)S-O-O-underset(O)underset(||)overset(O)overset(||)S-O-H` Two oxygen atoms are involved in peroxide linkage, hence oxidation number will be -1 (each). `H_(2)S_(2)O_(8)=underset(H)(2(+1))+underset(S)(2(x))+underset(O-O)(2(-1))+underset(O)(6(-2))=0` `x=+6` |
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