The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the orderA. `S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`B. `S_(2)O_(6)^(2-) lt S_(2)O_(4)^(2-) lt SO_(3)^(2-)`C. `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`D. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`

The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)

1.	The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the orderA. `S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`B. `S_(2)O_(6)^(2-) lt S_(2)O_(4)^(2-) lt SO_(3)^(2-)`C. `S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`D. `SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`
Answer» Correct Answer - C Oxidation state of S in `SO_(3)^(2-)` `x + (-2 xx 3) = - 2`, `x = +6-2=+4` Oxidation state of `S` in `S_(2)O_(4)^(2-)`. `2x+(-2xx4) = -2` `2x=+8-2=+6` `x = (+6)/(2) = +3` Oxidation state of S in `S_(2)O_(6)^(2-)` `2x + (-2xx6) = -2` `2x = +12-2 =10` `x = 10/2 = +5` Hence, increasing order of oxidation states of S is `S_(2)O_(4)^(3-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`.

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