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The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the orderA. `S_(2)O_(4)^(2-)gtS_(2)O_(6)^(2-)gtSO_(4)^(2-)gtSO_(3)^(2-)`B. `S_(2)O_(6)^(2-)gtSO_(3)^(2-)gtS_(2)O_(4)^(2-)gtSO_(4)^(2-)`C. `SO_(4)^(2-) gt S_(2)O_(6)^(2-)gtSO_(3)^(2-)gtS_(2)O_(4)^(2-)`D. `SO_(3)^(2-) gtSO_(4)^(2-)gtS_(2)O_(4)^(2-)gtS_(2)O_(6)^(2-)` |
Answer» Correct Answer - C `SO_(3)^(2-) rarr x + (-6)=-2 rArr x= +4` `SO_(4)^(-) rarr x + (-8)=-2rArr x=+6` `S_(2)O_(4)^(2-) rarr 2x+(-8)=-2rArr x=+3` `S_(2)O_(6)^(2-) rarr 2x+(-12)=-2 rArr x= +5` Hence `SO_(4)^(2-) gt S_(2)O_(6)^(2-) gt SO_(3)^(2-) gt S_(2)O_(4)^(2-)` |
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