The oxidation states of the most elecrtronegative element in the products of rection between BaO^(2) and diluent H_(2)SO_(4) are:

The oxidation states of the most elecrtronegative element in the produ

1.	The oxidation states of the most elecrtronegative element in the products of rection between BaO^(2) and diluent H_(2)SO_(4) are:
Answer» `-1` `+1` `-2` 0 Solution :`BaO_(2)+H_(2)SO_(4)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2)` Oxidation state of O in `BaSO_(4)`=-2"and in"H_(2)O_(2)`=-1`