1.

The oxidation states of the most electronegative element in the products of the reaction betweeen BaO_(2) with dil H_(2)SO_(4) are

Answer»

`-1`
`+1`
`-2`
0

Solution :`BaO_(2)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2)`
Most electronegative element in products is oxygen. In `H_(2)O_(2)` oxidation state of O is `-1` and in `BaSO_(4), -2`.


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