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The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` areA. `0` and `-1`B. `-1` and `-2`C. `-2` and `0`D. `-2` and `-1` |
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Answer» Correct Answer - D `BaO_(2) + H_(2) SO_(4) rarr BaSO_(4) + H_(2) O` The oxidation state of `O` in `BaSo_(4)` is `- 2`. The oxidation state of `O` in `H_(2) O_(2)` is `- 1`. |
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