The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` areA. `0` and `-1`B. `-1` and `-2`C. `-2` and `0`D. `-2` and `+1`

The oxidation states of the most electronegative elements in the produ

1.	The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` areA. `0` and `-1`B. `-1` and `-2`C. `-2` and `0`D. `-2` and `+1`
Answer» Correct Answer - B In `H_(2)O_(2)` oxygen shows `=-1` (peroxide) oxidation state and in `BaSO_(4)` oxygen shows `=-2` oxidation state.

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The oxidation states of the most electronegative elements in the products of the reaction between `BaO_(2)` and `H_(2)SO_(4)` areA. `0` and `-1`B. `-1` and `-2`C. `-2` and `0`D. `-2` and `+1`

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