The oxide of an element contains 67.67% of oxygen. Equivalent weight o

1.	The oxide of an element contains 67.67% of oxygen. Equivalent weight of the element is
Answer» `2.46` `3.82` `4.36` `4.96` Solution :`67.67=(16n)/(M)XX100" "("for"X_(2)O_(N))` `32.33=(2X)/(M)xx100` `impliesE=(X)/(n)=(32.33xx16)/(67.67xx2)=3.82`

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