The oxide that gives H_2O_2 on treatment with dilute H_2SO_4 is

1.	The oxide that gives H_2O_2 on treatment with dilute H_2SO_4 is
Answer» `PbO_2` `BaO_2 . 8H_2O + O_2` `MnO_2` `TiO_2` SOLUTION :OXIDES such as `BaO_2,Na_2O_2` etc. which contain peroxide linkage (i.e., -O-O- or `O_2^(2-)` ) on treatment with dilute `H_2SO_4` give `H_2O_2` but oxides (O = M = O, where M is the METAL ATOM) such as `PbO_2, MnO_2, TiO_2`, do not give `H_2O_2` on treatment with dilute `H_2SO_4`. `BaO_2. 8H_2O_((s)) + H_2SO_(4(aq)) to BaSO_(4(s)) + H_2O_(2(aq)) + 8H_2O_((l))`

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