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The p.d. across the capacitance of `2muF` in the figure along with is A. 10 VB. 60 VC. 28 VD. 56 V |
Answer» Correct Answer - B From figure, equivalent capacity of `3muF, 6muF and 3muF` condensers is `C_(p)=12muF`. Now, `C_(p)` and condenser of `2muF` are in series. Thus, p.d. across `2muF` condenser is, `V=((VC_(p))/(C_(1)+C_(p)))=(70xx12xx10^(-6))/(14xx10^(-6))=60V` |
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