The P^(H) of a dibasic acid is 3.699. Its molarity is

1.	The P^(H) of a dibasic acid is 3.699. Its molarity is
Answer» ` 2xx10^(-4)M` ` 4xx10^(-4) M` ` 2xx10^(-3) M` ` 1XX 10^(-4) M` Solution :` pH= 3. 699 ~~ 3.7 ` ` log [H^(+) ] = - pH=- 3.7 =-4 + 0.3 = overset(-) 4.3` ` [H^(+)] ="ANTI long " (overset( -)4.3) =2 xx10 ^(-4)N ` ` ["acid"] = 2xx 10 ^(-4) N RARR M = (N)/( n- F)= 1xx 10 ^(-4) M `

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